Answer
$y=Cx$
Work Step by Step
RECALL:
For positive real numbers M and N:
(1) $\ln{M} = \ln{N} \longrightarrow M=N$
(2) Product Rule: $\ln{M} + \ln{N} = \ln{(MN)}$
(3) Quotient Rule: $\ln{M} - \ln{N} = \ln{\left(\dfrac{M}{N}\right)}$
(4) Power Rule: $r\cdot ln {M} = \ln{(M^r)}$
Use the Product Rule to obtain:
$\ln{y}=\ln{x}+\ln{C}
\\\ln{y}=\ln{[x(C)]}
\\\ln{y}=\ln{(Cx)}$
Use rule (1) in above to obtain:
$\ln{y}=\ln{(Cx)} \longrightarrow y=Cx$
Thus,
$y=Cx$