College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.5 - Properties of Logarithms - 6.5 Assess Your Understanding - Page 460: 73

Answer

$\approx -3.880$

Work Step by Step

RECALL: The change-of-base formula for logarithms: $\log_a{b}=\dfrac{\log{b}}{\log{a}}$ Use a calculator and the formula above to obtain: $\log_{1/3}{71} = \dfrac{\log{71}}{\log{(1/3)}} \approx -3.880$
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