Answer
See below.
Work Step by Step
We know that $\log_a x+\log_a y=log_a (x\cdot y)$ and we know that $log_a x^n=n\cdot log_a x$, hence $\log_a{\frac{M}{N}}=\log_a{(MN^{-1})}=\log_a(M)+\log_a(N^{-1})=\log_a(M)-\log_a(N)$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 6 - Section 6.5 - Properties of Logarithms - 6.5 Assess Your Understanding - Page 460: 109
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