Answer
$9\log _{3}x$
Work Step by Step
We use the rules of logarithms to obtain:
$21\log _{3}\sqrt [3] {x}+\log _{3}9x^{2}-\log _{3}9=\log _{3}\dfrac {\left( \sqrt [3] {x}\right) ^{21}\times 9x^{2}}{9}=\log _{3}x^{9}=9\log _{3}x$
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