College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.5 - Properties of Logarithms - 6.5 Assess Your Understanding: 60

Answer

$-3\log _{2}x$

Work Step by Step

We use the rules of logarithms to obtain: $\log _{2}\left( \dfrac {1}{x}\right) +\log _{2}\dfrac {1}{x^{2}}=\log _{2}\left( \dfrac {1}{x}\times \dfrac {1}{x^{2}}\right) =\log _{2}\dfrac {1}{x^{3}}=-\log _{2}x^{3}=-3\log _{2}x$
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