College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.5 - Properties of Logarithms - 6.5 Assess Your Understanding - Page 459: 58

Answer

$\log _{3}\dfrac {u^{2}}{v}$

Work Step by Step

We use the rules of logarithms to obtain: $2\log _{3}u-\log _{3}v=\log _{3}u^{2}-\log _{3}v=\log _{3}\dfrac {u^{2}}{v}$
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