Answer
$\log_a{M} - \log_a{N}$
Work Step by Step
RECALL:
For any positive numbers $A$ and $B$, and real number $a\gt 0, a\ne1$,
$\log_a{\left(\dfrac{A}{B}\right)}=\log_a{A} - \log_a{B}$
Thus,
$\log_a{\left(\dfrac{M}{N}\right)}=\log_a{M} - \log_a{N}$
