College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.5 - Properties of Logarithms - 6.5 Assess Your Understanding - Page 459: 47

Answer

$2\ln x+\frac{1}{2}\ln ({1-x})$

Work Step by Step

We use the rules of logarithms to obtain: $\ln \left( x^2\sqrt {1-x}\right) =\ln x^{2}+\ln \sqrt {1-x}=2\ln x+\ln \sqrt {1-x}$$=2\ln x+\frac{1}{2}\ln ({1-x})$
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