College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.5 - Properties of Logarithms - 6.5 Assess Your Understanding - Page 459: 27

Answer

$4$

Work Step by Step

We know that $a^{\log_aM}=M$, hence $a^{\log_{a^k}M}=\sqrt[k] M$ Hence here $e^{\log_{e^2}16}=\sqrt[2] {16}=4$
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