Answer
$2$
Work Step by Step
RECALL:
(1) $\log_a{P} + \log_a{Q}=\log_a{(PQ)}$
(2) $\log_a{a} = 1$
(3) $\log_a{(a^n)}=n$
Use rule (1) above to obtain:
$\log_6{9} + \log_6{4} = \log_6{(9\cdot4)}=\log_6{36}$
Note that $36=6^2$. Thus, the expression above is equivalent to:
$\log_6{36}=\log_6{(6^2)}$
Use rule (3) above to obtain:
$\log_6{(6^2)} = 2$