## College Algebra (10th Edition)

$x=-4$
RECALL: $\ln{(x)}=y \longrightarrow e^y = x$ Use the rule above to obtain: $\ln{(e^{-2x})}=8 \longrightarrow e^8=e^{-2x}$ Use the rule $a^m=a^n \longrightarrow m=n$ to obtain: $8=-2x$ Divide both sides by $-2$ to obtain: $\frac{8}{-2} = \frac{-2x}{-2} \\-4 = x$