Answer
(a) $x\leq3$
(b) $x\lt-2$ or $x\gt3$
Work Step by Step
We simplify as follows:
(a) $3x-7\leq8-2x$
$5x\leq15$
$x\leq3$
(b) $x^{2}-x-6\gt0$
$(x-3)(x+2)\gt0$
$x\lt-2$ or $x\gt3$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 6 - Section 6.4 - Logarithmic Functions - 6.4 Assess Your Understanding - Page 448: 1
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