College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.3 - Exponential Functions - 6.3 Assess Your Understanding - Page 437: 111

Answer

See below.

Work Step by Step

By plugging in $h=1$ into the formula: $D(1)=5e^{-0.4\cdot1}=5e^{-0.4}\approx3.35$ By plugging in $h=6$ into the formula: $D(1)=5e^{-0.4\cdot6}=5e^{-2.4}\approx0.45$
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