College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.3 - Exponential Functions - 6.3 Assess Your Understanding - Page 437: 108

Answer

See below.

Work Step by Step

a) By plugging in $A_0=100,n=3$ into the formula: $A(3)=100e^{-0.35\cdot3}=100e^{-1.05}\approx34.99$ b) By plugging in $A_0=100,n=10$ into the formula: $A(10)=100e^{-0.35\cdot10}=100e^{-3.5}\approx3.02$
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