College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.3 - Exponential Functions - 6.3 Assess Your Understanding - Page 437: 106

Answer

See below.

Work Step by Step

a) By plugging in $h=2$ into the formula: $p(2)=760e^{-0.145\cdot2}=760e^{-0.29}\approx568.68$ b) By plugging in $h=10$ into the formula: $p(10)=760e^{-0.145\cdot10}=760e^{-1.45}\approx178.27$
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