College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.2 - One-to-One Functions; Inverse Functions - 6.2 Assess Your Understanding - Page 422: 89

Answer

Conditions Either $f(x) = |x| = x$ for $x \ge 0$ OR $f(x) = |x| = -x$ for $x \le 0$ Then Inverse functions $f^{-1}(x) = x$ for $x \ge 0$ In second case $f^{-1}(x) = -x$ for $x \le 0$

Work Step by Step

Function $f(x) = |x|$ is not one to one as $f(x) = f(-x) $ But it will become one to one if we put restriction on domain Like Either $f(x) = |x| = x$ for $x \ge 0$ OR $f(x) = |x| = -x$ for $x \le 0$ But not both It is very simple that, Inverse function in first case will be $f^{-1}(x) = x$ for $x \ge 0$ In second case $f^{-1}(x) = -x$ for $x \le 0$
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