Answer
$a=\pm5$
Work Step by Step
$f(g(x))=f(2x+a)=3(2x+a)^2-7=3(4x^2+4ax+a^2)-7$
The fact that it crosses the y-axis at $68$ means that $f(g(0))=68$.
Hence here $3(4\cdot0^2+4a\cdot0+a^2)-7=68\\3a^2=75\\a^2=25\\a=\pm5$
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