College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.1 - Composite Functions - 6.1 Assess Your Understanding - Page 409: 54

Answer

$x$

Work Step by Step

$f(f(x))=f(\frac{x+1}{x-1})=\dfrac{\frac{x+1}{x-1}+1}{\frac{x+1}{x-1}-1}=\dfrac{\frac{x+1}{x-1}+\frac{x-1}{x-1}}{\frac{x+1}{x-1}-\frac{x-1}{x-1}}=\dfrac{\frac{2x}{x-1}}{\frac{2}{x-1}}=\dfrac{2x}{2}=x$
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