Answer
See below.
Work Step by Step
Let $f(x)=| x|$ and $g(x)=2x^2+3$.
Then $H(x)=f\circ g=f(g(x))=f(2x^2+3)=|2x^2+3|$.
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 6 - Section 6.1 - Composite Functions - 6.1 Assess Your Understanding - Page 409: 52
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