Answer
y-intercepts:
$y=\sqrt {12}, -\sqrt {12}$
x-intercept(s):
$x=4$
Work Step by Step
$3x+y^2=12$
y-intercepts:
$3(0)+y^2=12$
$y^2=12$
$y=\sqrt {12}, -\sqrt {12}$
x-intercept(s):
$3x=(0)^2=12$
$3x=12$
$x=4$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.