Answer
See below.
Work Step by Step
The x-intercepts are when $y=0$, thus here $\frac{x^2-1}{x^2-4}=0\\x^2-1=0\\x^2=1\\x=\pm1$
The y-intercepts are when $x=0$, thus here $y=\frac{0^2-1}{0^2-4}=\frac{-1}{-4}=0.25$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 5 - Section 5.3 - The Graph of a Rational Function - 5.3 Assess Your Understanding - Page 365: 1
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