Answer
$f(x)=x^3(x+4)(x-2)$
Work Step by Step
If $a$ is a zero of a function with multiplicity $b$ then $(x-a)^b$ is a “multiplier” of the function.
Hence here $f(x)=kx^3(x+4)(x-2)$
$(-2,64)$ is on the graph thus $k\cdot(-2)^3(2)(-4)=64\\64k=64\\k=1$
So $f(x)=x^3(x+4)(x-2)$