Answer
$f(x)=(x+2)(x-2)(x-3)=x^3-3x^2-4x+12.$
Work Step by Step
We are given that the degree is 3, and the zeros are -2, 2 and 3, hence a good function is: $f(x)=(x+2)(x-2)(x-3)=x^3-3x^2-4x+12.$
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