Answer
$x=4$
Work Step by Step
$(x-4)^2\leq0$ But $(x-4)^2$ is non-negative, thus the solution set is when $(x-4)^2=0\\x-4=0\\x=4$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 4 - Section 4.5 - Inequalities involving Quadratic Functions - 4.5 Assess Your Understanding - Page 315: 39
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