Answer
$(-\infty,-4]\cup[4,\infty)$.
Work Step by Step
The expression under the square root must be non-negative. Thus $x^2-16\geq0\\x^2\geq16\\|x|\geq4$
So the domain is $(-\infty,-4]\cup[4,\infty)$.
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 4 - Section 4.5 - Inequalities involving Quadratic Functions - 4.5 Assess Your Understanding - Page 314: 23
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