Answer
$(x+6)^2+y^2=7$
Work Step by Step
The general equation for a circle with radius $r$ and centre $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$, hence here the equation is: $(x-(-6))^2+(y-0)^2=\sqrt7^2\\(x+6)^2+y^2=7$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 4 - Section 4.4 - Build Quadratic Models from Verbal Descriptions and From Data - 4.4 Assess Your Understanding - Page 311: 34
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