## College Algebra (10th Edition)

$x=50$
Add $15x$ and $900$ to both sides of the equation to obtain: \begin{array}{ccc} &60x-900+15x+900&=&-15x+2850+15x+900 \\&75x&=&3750\end{array} Divide 75 on both sides of the equation to obtain: $x=\dfrac{3750}{75} \\x=50$