Answer
(a) No
(b) If x=-2, f(x)=-1
The point is (-2, -1)
(c) If x=2, f(x)=1/3
The point is $(2, \frac{1}{3})$
Work Step by Step
(a) We can prove this by placing the values into the equation and verifying the equality:
$\dfrac{1}{4}=\dfrac{1}{1+4}$
$\dfrac{1}{4}=\dfrac{1}{5}$ FALSE
(b) Calculate f(-2):
$f(-2)=\dfrac{-2}{-2+4}$
$f(-2)=\dfrac{-2}{2}$
$f(-2)=-1$
The point is (-2, -1)
(c) Calculate f(2):
$f(2)=\dfrac{2}{2+4}$
$f(2)=\dfrac{2}{6}$
$f(2)=\frac{1}{3}$
The point is $(2, \frac{1}{3})$
