Answer
$y=\sqrt{-x-3}+2$
Work Step by Step
$f_{0}(x)=\sqrt{x}$
$(1)$ Shift up 2 units$\qquad...\qquad f_{1}(x)=f_{0}(x)+2=\sqrt{x}+2$
$(2)$ Reflect about the $y$ -axis$\qquad...\qquad f_{2}(x)=f_{1}(-x)=\sqrt{-x}+2$
$(3)$ Shift left 3 units$\qquad...\qquad f_{3}(x)=f_{2}(x+3)=\sqrt{-(x+3)}+2$
$y=\sqrt{-x-3}+2$