College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 3 - Section 3.3 - Properties of Function - 3.3 Assess Your Understanding - Page 236: 105

Answer

$-8\leq x\lt -3$ Or, in interval notation: $[-8,\ -3)$

Work Step by Step

We solve: $14\lt 5-3x\leq 29$ We subtract 5: $14-5\lt -3x\leq 29-5$ $9\lt -3x\leq 24$ And divide by $-3$: $-3\gt x\geq-8$ $-8\leq x\lt -3$ Or, in interval notation: $[-8,\ -3)$
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