## College Algebra (10th Edition)

$2\sqrt{10}$
We find the distance between the points (3,-6) and (1,0) using the distance formula: $d=\sqrt{(1-3)^{2}+(0--6)^{2}}$ $\sqrt{(-2)^{2}+6^{2}}$ $\sqrt{4+36}$ $\sqrt{40}$ $\sqrt{4*10}$ $2\sqrt{10}$