College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 3 - Section 3.2 - The Graph of a Function - 3.2 Assess Your Understanding: 1

Answer

x-intercepts: $(-4,0),(4,0)$ y-intercepts: $(0,-2),(0,2)$

Work Step by Step

The intercepts of the equation $x^2 + 4y^2 = 16$ are: For $x$-intercepts, set $y=0$: $x^{2}+4(0)^{2}=16$ $x^{2}=16$ $x=\pm 4$ $(-4,0),(4,0)$ For $y$-intercepts, set $x=0$: $(0)+4y^{2}=16$ $4y^{2}=16$ $y^{2}=4$ $y=\pm 2$ $(0,-2),(0,2)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.