Answer
$\begin{array}{ll}
a. & -1\\
b. & -2\\
c. & -4\\
d. & -2x^{2}-x-1\\
e. & 2x^{2}-x+1\\
f. & -2x^{2}-3x-2\\
g. & -8x^{2}+2x-1\\
h. & -2x^{2}-4xh-2h^{2}+x+h-1
\end{array}$
Work Step by Step
$f(x)=-2x^{2}+x-1$
$\begin{array}{lll}
(a)\ f(0) & (b)\ f(1) & (c)\ f(-1)\quad \\
=-2(0)^{2}+0-1 & =-2(1)^{2}+1-1 & =-2(-1)^{2}+(-1)-1\\
=-1 & =-2 & =-2-2\\
& & =-4
\end{array}$
$\begin{array}{ll}
(d)\ f(-x) & (e)\ -f(x)\\
=-2(-x)^{2}+(-x)-1 & =-(-2x^{2}+x-1)\\
=-2x^{2}-x-1\quad & =2x^{2}-x+1\\
&
\end{array}$
$\begin{array}{lll}
(f)\ f(x+1) & (g)\ f(2x) & \\
=-2(x+1)^{2}+(x+1)-1 & =-2(2x)^{2}+(2x)-1 & \\
=-2(x^{2}+2x+1)+x+1-1 & =-8x^{2}+2x-1 & \\
=-2x^{2}-4x-2+x & & \\
=-2x^{2}-3x-2 & & \\
& &
\end{array}$
$(h)\ f(x+h)=-2(x+h)^{2}+(x+h)-1$
$=-2(x^{2}+2xh+h^{2})+x+h-1$
$=-2x^{2}-4xh-2h^{2}+x+h-1$
