Answer
See graph
Work Step by Step
The is the general form of a circle,
$(x-h)^2+(y-k)^2=r^2$
$(h,k)$ is the center of the circle.
Thus $(0,3)$ is the center.
The radius is $\sqrt{16}=4$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 3 - Cumulative Review - Page 271: 13
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