Answer
See below.
Work Step by Step
The general equation for a circle with radius $r$ and centre $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$, hence our equation: $x^2+y^2+4x-2y-4=0\\(x+2)^2-4+(y-1)^2-1-4=0\\(x+2)^2+(y-1)^2=9=3^2$
Thus the center is $(-2,1)$ and the radius is $3$. Using a graphing utility:
