College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.5 - Variation - 2.5 Assess Your Understanding - Page 194: 53

Answer

$\frac{8}{125}$

Work Step by Step

$(\frac{4}{25})^{\frac{3}{2}}=((\frac{2}{5})^2)^{\frac{3}{2}}=(\frac{2}{5}))^{2\cdot\frac{3}{2}}=(\frac{2}{5}))^3=\frac{8}{125}$
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