Answer
See below.
Work Step by Step
$\frac{5}{x+3}+\frac{x-2}{x^2+7x+12}=\frac{5(x+4)}{(x+3)(x+4)}+\frac{x-2}{(x+3)(x+4)}=\frac{5(x+4)+x-2}{(x+3)(x+4)}=\frac{5x+20+x-2}{(x+3)(x+4)}=\frac{6x+18}{(x+3)(x+4)}=\frac{6(x+3)}{(x+3)(x+4)}=\frac{6}{x+4}$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 2 - Section 2.5 - Variation - 2.5 Assess Your Understanding - Page 194: 52
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