Answer
$1.82$
Work Step by Step
$hp=kvd^3$, hence here $36=k\cdot75\cdot2^3$, thus $k=0.06$
Hence if $hp=45$ and $v=125$, then $d=\sqrt[3] {\frac{hp}{kv}}=\sqrt[3] {\frac{45}{0.06\cdot125}}\approx1.82$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 2 - Section 2.5 - Variation - 2.5 Assess Your Understanding - Page 193: 41
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