College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.3 - Lines - 2.3 Assess Your Understanding - Page 182: 146

Answer

$x^4y^{16}$

Work Step by Step

$(\frac{x^2y^{-3}}{x^4y^5})^{-2}=(\frac{1}{x^2y^8})^{-2}=(x^2y^8)^2=x^4y^{16}$
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