Answer
$\color{blue}{y=\dfrac{1}{2}x+\dfrac{5}{2}}$
Work Step by Step
RECALL:
(1) The slope-intercept form of a line's equation is: $y=mx+b$, where $m$=slope and $b$ = y-intercept.
(2) The slope of a line that contains the points $(x_1)$ and $(x_2, y_2)$ can be found using the formula: $m=\dfrac{y_2-y_1}{x_2-x_1}$
Solve for the slope of the line using the two given points on the line to obtain:
$m=\dfrac{2-3}{-1-1}
\\m=\dfrac{-1}{-2}
\\m=\dfrac{1}{2}$
Thus, the tentative equation of the line is:
$y=\dfrac{1}{2}x+b$
To find the value of $b$, substitute the x and y values of the point $(1, 3)$ into the tentative equation above to obtain:
$y=\dfrac{1}{2}x+b
\\3=\dfrac{1}{2}(1)+b
\\3=\dfrac{1}{2}+b
\\3-\dfrac{1}{2}=b
\\\dfrac{6}{2}-\dfrac{1}{2}=b
\\\dfrac{5}{2}=b$
Therefore, the equation of the line is:
$\color{blue}{y=\dfrac{1}{2}x+\dfrac{5}{2}}$.