Answer
See below.
Work Step by Step
If we plug in the respective $x$ and $y$ values of $(x,y)$, we can check if it satisfies the equation, if it does, it is on the graph, if it doesn't it is not on the graph.
Hence here: $(0,1)\rightarrow0^2+4\cdot1^2=0+4=4$, so it is on the graph
$(2,0)\rightarrow(2)^2+4\cdot0^2=4+0=4$, so it is on the graph
$(2,0.5)\rightarrow(2)^2+4\cdot0.5^2=4+1=5\ne4$, so it is not on the graph