Answer
See below.
Work Step by Step
If we plug in the respective $x$ and $y$ values of $(x,y)$, we can check if it satisfies the equation; if it does, it is on the graph, and if it doesn't it is not on the graph.
Hence here: $(0,0)\rightarrow0^3-2\sqrt0=0-0=0$, so it is on the graph
$(1,1)\rightarrow1^3-2\sqrt1=1-2=-1\ne1$, so it is not on the graph
$(1,1)\rightarrow1^3-2\sqrt1=1-2=-1$, so it is on the graph