College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 2 - Section 2.2 - Graphs of Equations in Two Variables; Intercepts; Symmetry - 2.2 Assess Your Understanding - Page 165: 14

Answer

See below.

Work Step by Step

If we plug in the respective $x$ and $y$ values of $(x,y)$, we can check if it satisfies the equation; if it does, it is on the graph, and if it doesn't it is not on the graph. Hence here: $(0,0)\rightarrow0^3-2\sqrt0=0-0=0$, so it is on the graph $(1,1)\rightarrow1^3-2\sqrt1=1-2=-1\ne1$, so it is not on the graph $(1,1)\rightarrow1^3-2\sqrt1=1-2=-1$, so it is on the graph
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