Answer
F
Work Step by Step
$P(T)=2/3,P(H)=1/3$. Since the tosses are independent, the possiblity of each event is the product of the two tosses individually. Thus $P(TT)=P(T)P(T)=2/3\cdot2/3=4/9$, $P(HH)=P(H)P(H)=1/3\cdot1/3=1/9$, $P(TH)=P(T)P(H)=2/3\cdot1/3=2/9$, $P(HT)=P(H)P(T)=1/3\cdot2/3=2/9$, thus the answer is F
