Answer
14 million males 18 years old and older are widowed or divorced.
79.3 million males 18 years old and older are married, widowed or divorced.
Work Step by Step
Set $A$ consists of males 18 years old and older who are married, and set $B$ consists of males 18 years old and older who are widowed, and set $C$ consists of males 18 years old and older who are divorced.
The first question asks for the union of sets $B$ and $C$
Using the Counting Formula for sets:
$n(B\cup C)=n(B)+n(C)-n(B\cap C)$
According to the survey, there isn't anybody who is both widowed and divorced; therefore:
$n(B\cap C)=0$
$n(B\cup C)=3.1+10.9-0=14$
14 million males 18 years old and older are widowed or divorced.
The second question asks for the union of sets $A$, $B$, and $C$.
Using the Counting Formula for sets:
$n(A\cup B\cup C)=n(A)+n(B+n(C)-n(A\cap B)-n(B\cap C)-n(A\cap C)+n(A\cap B\cap C)$
According to the survey there isn't anybody who is in either intersection of these sets; therefore:
$n(A\cup B\cup C)=n(A)+n(B+n(C)-n(A\cap B)-n(B\cap C)-n(A\cap C)+n(A\cap B\cap C)=65.3+3.1+10.9-0-0-0+0=79.3$
79.3 million males 18 years old and older are married, widowed, or divorced.
