College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 10 - Section 10.1 - Counting - 10.1 Assess Your Understanding: 31

Answer

14 million males 18 years old and older are widowed or divorced. 79.3 million males 18 years old and older are married, widowed or divorced.

Work Step by Step

Set $A$ consists of males 18 years old and older who are married, and set $B$ consists of males 18 years old and older who are widowed, and set $C$ consists of males 18 years old and older who are divorced. The first question asks for the union of sets $B$ and $C$ Using the Counting Formula for sets: $n(B\cup C)=n(B)+n(C)-n(B\cap C)$ According to the survey, there isn't anybody who is both widowed and divorced; therefore: $n(B\cap C)=0$ $n(B\cup C)=3.1+10.9-0=14$ 14 million males 18 years old and older are widowed or divorced. The second question asks for the union of sets $A$, $B$, and $C$. Using the Counting Formula for sets: $n(A\cup B\cup C)=n(A)+n(B+n(C)-n(A\cap B)-n(B\cap C)-n(A\cap C)+n(A\cap B\cap C)$ According to the survey there isn't anybody who is in either intersection of these sets; therefore: $n(A\cup B\cup C)=n(A)+n(B+n(C)-n(A\cap B)-n(B\cap C)-n(A\cap C)+n(A\cap B\cap C)=65.3+3.1+10.9-0-0-0+0=79.3$ 79.3 million males 18 years old and older are married, widowed, or divorced.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.