College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.4 - Radical Equations; Equations Quadratic in Form; Factorable Equations - 1.4 Assess Your Understanding: 80

Answer

$x=0$ or $x=-7$ or $x=1$

Work Step by Step

We solve by factoring: $x^{3}+6x^{2}-7x=0$ $x(x^{2}+6x-7)=0$ $x(x+7)(x-1)=0$ $x=0$ or $x+7=0$ or $x-1=0$ $x=0$ or $x=-7$ or $x=1$
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