Answer
$\displaystyle x=-\frac{1}{3}$
Work Step by Step
We solve by factoring:
$(3x+4)^{2}-6(3x+4)+9=0$
$[(3x+4)-3][(3x+4)-3]=0$
$(3x+1)^2=0$
$3x+1=0$
$x=-\frac{1}{3}$
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