College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.4 - Radical Equations; Equations Quadratic in Form; Factorable Equations - 1.4 Assess Your Understanding: 50

Answer

$x=-1$ or $x=-\displaystyle \frac{7}{2}$

Work Step by Step

We solve by factoring: $(2x+5)^{2}-(2x+5)-6=0$ $[(2x+5)-3][(2x+5)+2]=0$ $(2x+2)(2x+7)=0$ $(2x+2)=0$ or $(2x+7)=0$ $x=-1$ or $x=-\displaystyle \frac{7}{2}$
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