Answer
$x=5$
Work Step by Step
We solve:
$(3x+1)^{1/2}=4$
$[(3x+1)^{1/2}]^{2}=(4)^{2}$
$3x+1=16$
$3x=15$
$x=15/3$
$x=5$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Section 1.4 - Radical Equations; Equations Quadratic in Form; Factorable Equations - 1.4 Assess Your Understanding - Page 118: 35
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