Answer
$-2+2i$
Work Step by Step
Recall, $i=\sqrt{-1}$, so $i^{2}=-1$. Thus, we use the distributive property to obtain:
$(1+i)^{3}$
$=(1+i)(1+i)(1+i)$
$=(1+2i+i^{2})(1+i)$
$=(1+2i+-1)(1+i)$
$=(2i)(1+i)$
$=2i+2i^{2}$
$=2i+2*-1$
$=-2+2i$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 1 - Section 1.3 - Complex Numbers; Quadratic Equations in the Complex Number System - 1.3 Assess Your Understanding - Page 112: 43
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