College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Section 1.1 - Linear Equations - 1.1 Assess Your Understanding - Page 92: 97

Answer

$550$ calories for lunch, $675$ calories for breakfast, $800$ calories for dinner.

Work Step by Step

Let $x$ be the calories from lunch, then $x+125$ is the calories from breakfast, $2x-300$ is the calories from dinner. Thus the equation is: $x+x+125+2x-300=2025\\4x-175=2025\\4x=2200\\x=550$ Thus there were $550$ calories for lunch, $675$ calories for breakfast, $800$ calories for dinner.
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